01-18-2005, 03:40 AM #1
- Join Date
- Jan 2005
Powering LED's : use a resistor or not?
I was looking at the 8/8/8 Tutorial number 2 about hooking up an LED to a digital output. My question is this: Why isn't there a need for resistor to be placed before the LED so it doesn't burn out? On other IO boards cockpit builders use, to power a LED requires a resistor to restrict current so the LED doesn't burn out. Is there some internal circuitry in the 8/8/8 to protect a LED from burning out? Does the 0/16/16 act the same way?
01-18-2005, 05:21 AM #2phidgetsGuest
The 8/8/8 outputs 5 volts which isn't enough to burn out an LED.
The 0/16/16 it very different it doesn't have it's own power source. It switches to ground on the power source you supply.
Here are the differences of the boards side by side:
By adacho in forum I/O Interfacing and HardwareReplies: 2Last Post: 08-19-2010, 05:35 AM
By esa1203 in forum General Builder Questions All Aircraft TypesReplies: 5Last Post: 07-13-2010, 06:45 PM
By mterm in forum I/O Interfacing and HardwareReplies: 2Last Post: 04-09-2009, 08:34 PM
By weyes in forum OpenCockpits General DiscussionReplies: 16Last Post: 03-18-2009, 04:41 AM
By Paul G in forum Cockpit Parts and Motion PlatformsReplies: 15Last Post: 09-04-2008, 05:04 AM